MySQL - How to do an Oracle RANK() OVER(ORDER BY score DESC) -

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I'm familiar with Oracle and normally rank one () like this: 

  Score | Rank -------------- 100 | 1 100 1992. 3 98 4 98. 4 98. 4 97 7 / << code>  
 I have not found a foggeet to do this in MySQL - after watching here, I have found:  
  SET @prev_value = tap; Set @rank_count = 0; SELECT score, CASE WHEN @prev_value = Score then @rank_count WHEN @prev_value: = Score then Ranked as @rank_count: = Rank_con + 1Ed Rank ...   
 But this Returns as follows:  
  Score | Rank -------------- 100 | 1 100 1992. 2 98. 3 98 4 98. 4 97 5   
 That which I wanted was not the same.   
 
 
 Add another variable:  
  SET @prev_value = NULL; Set @rank_count = 0; SET @Rank_increasing = 0; SELECT score, @Rank_increasing: line_num as @rank_increasing + 1, case when @prev_value = scores again @rank_count WHEN @prev_value: = score then @rank_count: = @ rank_increasing as the AD rank ...

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