Is there a way to have an updated drop down menu that pull records from database using php -

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  & lt;? Php $ sql = "सॉफ़्टवेयर_टेबल से सॉफ्टवेयर का चयन करें"; $ Qry = mysql_query ($ एसक्यूएल); $ = Mysql_num_rows ($ qry) गिनती; $ पंक्ति = mysql_fetch_array ($ qry); $ डेटा = [ 'SOFTWARE_NAME']; ? & Gt; & Lt;? Php के लिए ($ i = 0; $ i & lt; = गणना ($ डेटा); $ i ++) {? & Gt; & Lt; चयन करें नाम = "सॉफ़्टवेयर_नाम" & gt; & Lt; option vale = "& lt;? Php $ डेटा [$ i]? & Gt;" & gt; $ डेटा & lt; / option & gt; }? & Gt;   
 'मुझे यह नहीं पता है कि यह संभव है, लेकिन मुझे क्या करना है, यह है कि जब मैं सॉफ्टवेयर_टेबल से नए सॉफ़्टवेयर जोड़ता हूं। सॉफ़्टवेयर के लिए मेरा ड्रॉप-डाउन मेनू अद्यतन करने के लिए डेटाबेस से इसके विकल्प का मान प्राप्त करेगा। मैं इसके लिए लूप का इस्तेमाल करने की सोच रहा हूं, लेकिन मैं नहीं जानता कि कैसे शुरू करना है या यह वाकई संभव है।  
 उदाहरण मेरे ड्रॉप-डाउन मेनू में मेरे पास 3 विकल्प मान है।  
  1.MS ऑफिस 2. एटोडेस्क 3.PRIMAVERA   
 और फिर मैं डेटाबेस से एक अन्य सॉफ़्टवेयर जोड़ता हूं जो कि विंडो 8 ।  
 मैं अपने ड्रॉप-डाउन मेनू को उन 4 मान रखना चाहता हूं।   
 
 
 निम्न कोड का उपयोग करने की कोशिश करें -  
  $ sql = "सॉफ़्टवेयर_टेबल से सॉफ़्टवेयर चुनें"; $ Qry = mysql_query ($ एसक्यूएल); ? & Gt; & Lt; चयन करें नाम = "सॉफ़्टवेयर_नाम" & gt; & Lt;? Php जबकि ($ पंक्ति = mysql_fetch_array ($ qry)) {$ data = $ row ['software_name']; ? & Gt; & Lt; option vale = "& lt;? Php $ डेटा;; & gt;" & gt; & lt;? Php $ डेटा गूंज; ? & Gt; & lt; / विकल्प & gt; & Lt;? Php}? & Gt; & Lt; / चयन & gt;

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