how to edit a line (overwright and replace) in python -

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I have a file and I need to edit a specific line within that file

This line needs to be edited: 

  "file: /// c: /xxxxxxx/nameList.json#/"   
 In:  
  & lt; Xxxx = "xxxx: //xxxx.com/xxxx//nameList.md" & gt; Name list / xxxxxx /   
 How should I do this?  
 Note that somehow I need to store "name list" I am writing a script and part of the "name list" is different for different files  
 Additional information:  
     
  1.  
     Whatever is to be done in front of the name's name "and whatever" after the name list "....  < / Li> 
  2.  
     But string "name list" is arbitrary for various files. For example, the first file will have name 1 list, the second name will be 2 ... etc. I need to keep nameListX for different files     
     
     
      Regex = re.compile ("file: /// c: / ([^ /] +) /nameList.json#/") replacer = lambda g: '& lt; {0} = "{0}: // {0} .com / {0} //nameList.md" & gt; Open the name list / {0} /'.format(g.groups()[0]) ("Output.txt", "w"): in the open for line ("input.txt"): F.write (re.sub (regex, replacer, line))   
     Maybe ... I do not know what else xxxx has to do with xxxx in the first one      
     If you want "nameList" section then  
      regex = re.compile ("file: /// c: / [^ /] + / ([.] +) \ .json # / ") replacer = lambda g: '& lt; Xmlns = "Http://blahblah.com/sub1//{0}.md">{0} /xxxx/'.format(g.groups()[0]) with open (" output.txt " , "W"): for open in the line ("input.txt"): f.write (re.sub (regex, replacer, line))    < / Html>

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