jQuery to return the wrapper of the content instead of only the content -

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इस सवाल का पहले से ही एक उत्तर है: < / P>

  • 26 उत्तर

    मान लें कि मेरे पास निम्न HTML है <पूर्व> & lt; लेख & gt; & Lt; लेख आईडी = "ए 1" & gt; & Lt;! - आईडी = "a1" - & gt; के साथ लेख की सामग्री & Lt; / लेख & gt; & Lt; लेख आईडी = "ए 2" & gt; & Lt;! - id = "a2" - & gt; के साथ लेख की सामग्री & Lt; / लेख & gt; & Lt; लेख आईडी = "ए 3" & gt; & Lt;! - आईडी = "ए 3" के साथ लेख की सामग्री - & gt; & Lt; / लेख & gt; & Lt; / लेख & gt;

    jQuery का उपयोग करके, मैंने निम्न किया 

      var x = $ ("# a2")। Html ();   
     अब, वैरिएबल  x  Contian होगा:  
      & lt;! - id = "a2" के साथ लेख की सामग्री - & gt;   
     हालांकि, मुझे  x  होना चाहिए:  
      & lt; लेख आईडी = "ए 2" & gt; & Lt;! - id = "a2" - & gt; के साथ लेख की सामग्री & Lt; / लेख & gt;   
     मैंने कोशिश की:  
      var x = $ ("# a2")। माता पिता ()। Html ();   
     लेकिन इसने तीनों लेखों को वापस कर दिया, जो कि मैं क्या चाहता हूं। मैं केवल लेख  a2  चाहता हूं मैं ऐसा कैसे कर सकता हूं?  
     धन्यवाद।   
     
     
     संपत्ति का उपयोग करने की कोशिश करें,  
      var x = $ ("# a2") [0] .outerHTML;

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