function - How to return a valid iterator in C++? -

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I am writing a function to find the element in vector and return an element to that element: 

  vector & lt; Int & gt; :: errator circular (vector & lt; int & gt; ivec, int target) {auto it = ivec.begin (); While (this! = Ivec.end ()) {If (* this = target) it returns; Other ++; } Return ivec.end (); }   
 Then I copy the return itator to another iterator. I can correctly determine the iterator:  
  vector & lt; Int & gt; Number {1,2,3,4,5,6,7,8,9,10}; Auto ether = sediment (number, 5); The court's & lt; & Lt; * ITER;   
 Output is 5. But, when I increment / decrease the increment, then something is wrong:  
  - iter; The court's & lt; & Lt; * ITER; // I think the output should be 4 but the output is 134281917!   
 Is the price for search wrong?   
 
 
  if (* this = goal) return it;   
 Assigns this  target  to  * it . Since  target  is  5 , the expression value is also  5 , which is equal to  true . Thus, with a nonzero  target , your function will specify the first element of  target  to  ivec  and return to  ivec.begin ( ) . It should be clear that results in undefined behavior that is repeated.  
 Note that the quarrel with both G ++ and  -white  (it also emits a warning). You should always compile your code in the high alert settings.

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