bash - Replace all bullets with spaces -
How do I change tablets with spaces (octal value: 225, hexadecimal value: 95)? The following commands:
resonance 'a ?? Test '| | Tr '\ 225' '' echo '' 'test' | Awk '{gsub (/ \ 225 /, ""); Print $ 0} 'echo' '' test '| Sed 's / \ o225 / / g' echo '? Test '| | LANG = '' sed 's / \ o225 / / g' echo '? Test '| Sed's / \ x95 / / g '
The above command does not work.
Let's see why your current attempts are failing:
$ Echo 'â ?? Test '| Hexdump-c00000000 e280 a2 74 65 73 74 a. ... exam. | 00000008 These pills are actually three bytes - e280 a2 , none even 0x95 . A correct CAD expression works fine:
echo '¢ ?? Test '| Sed -e's / â? ¢ / / g ' ... or (Bash-extended syntax is not available in / bin / sh ) ... resonance 'a ?? Test '| Sed -e $ s @ \ xe2 \ x80 \ xa2 @ @g ' ... or (using bash-builtin replacement functionality):
< Code> S = 'â ?? ¢ test 's orig =' a 'in the original string ?? ¢ '# s2 = $ {s // "$ orig" / $ new} # result s2 ... or (to change the # object to replace the new object) According to the GNU sed extension, per @ knave) ...
echo 'â ?? Test '| Sed's @ \ xe2 \ x80 \ xa2 @ @ '
Comments
Post a Comment