timeout - Haskell -- Forcing strict evaulation with a weird, recursive type -

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I asked a question about how to enforce timeliness to enforce strict evaluation. seq / $! Using is maximum time, and deepseq works for anything that is a member of NFData , but what if we use a weird recursive type are doing? Let's say we have the following: 

  import control. Deepseek Import Control Silence Random Import Data Probably importing system Timeout new type A = A {runA :: A -> Int - & gt; Rand StdGen Bool} - A call to run with it is always example1 :: A example 1 = A (\ ii -> (if i> again see) randomR (True, False) as input and Incorrectly return)) - A call to run with it, as the first input example 2: A will not end with example 2 = A (\ _ _ -> run A example 2 example 2 0) Depends on - Example 1 will end with example 2 or 3 not with example 3: an example 3 = A (\ a _ -> run AA 0)   
 Have Can write a timeout function that determines that some value  x  type  A  will end within a given time when we  runA xx 0  Will you call on? We can try to use it as  seq :  
  testTimeout :: A -> Io (probably Boyle) testtimeout X = timeout 1000 EvalRandIO $! However, this does not work for  example2  and  example3  because the call is assessed as  run A  WHNF, but then hangs because The calculation never ends, the same thing will not be compiled with  deepseq  (i.e.  $ !! ), because we have to go to  NFData  For example  Rand is required StdGen bool  So, how can we implement this example that the rationale of the strict evaluation / scheduling Somewhere What happens? Or is there any other way to do this?   
 
 
 It appears that  timeout  Performs the action in time, as a result Inside is not evaluated. This is right. If we use  
  (> gt; = (return $!)) Then :: Monad m = & gt; I'm a - & gt; As you know, a type of return creates  m a  <  
  return $! By doing , we are saying that we do not make  m , and therefore complete the result until the action is completed. There is a more functional function here.  
  evalM m = Results result & lt; - Results of `seq` return result   
 You can also do this with NFData (which is not required for  Bool  but if you enter  [ A]  you can do so:  
  (& gt; & gt; = (return $ !!)) :: (Monad M, NFData A) => I - One -> MA   
 more executed:  
  force mm = result < `Depth` return result

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