c++ - Difference between std::string and std::u16string (or u32string) -

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I have mentioned the following terms before asking here:


But they do not question me, see the simple code below: 

  # include & lt; Iostream & gt; #include & lt; string & gt; using namespace std; Int main () {char16_t x [] = {'a', 'b', 'c', 0}; U16string arr = x; Cout & lt; & Lt; "Arr.length =" & lt; & Lt; Arr.length () & lt; & Lt; Endl; For (auto i: arr) COAT & lt; & Lt; I & lt; & Lt; "\ N"; }   
 Output is:  
  arr.length = 3 // a + b + c 97 98 99   
 Given that,  std :: u16string  contains  char16_t  and should not be  char  output:  
 < Code> arr.length = 2 // ab + c (\ 0) & lt; Combinations 'A' and 'B' & gt; 99   
 Please forgive me for a novice question. My requirement is to be clear about the concept of the new C ++ 11 string.  
  Edit :  
 From the north of Jonathan, I have found a way to escape. My point in my question is that  char16_t  To get started, so that  arr  is the length of  2  (i.e  ab ,  c \ 0 ). FYI returns a different result below:  
  char x [] = {'a', 'b', 'c', 0}; U16string arr = (char16_t *) X; // Perhaps undefined behavior   
 output:  
  arr.length = 3 25185 99 32767    
 
 
 No, you have created an array of four elements, the first element  'a'  was converted to  char16_t , the second  'b'  is converted to  char16_t  etc.  
 Then you have a  u16string  The array that changes (turns into an indicator), which reads each element up to the null terminator.

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