How to convert Unicode Escape Sequence to Unicode String in Haskell -

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I have "3619 \ 3657 \ 3634 \ 3609 \ 3648 \ 3592 \ 3657 \ 3648 \ 3621 \ 3657 \ 3591 " which I want to decode it. I tried searching the Unicode library without success.

prelude & gt; PutStrLn "\ 3619 \ 3657 \ 3634 \ 3609 \ 3648 \ 3592 \ 3657 \ 3648 \ 3621 \ 3657 \ 3591"> a £ ¹ ?? ¸ ² ¸ ¸¸¸¸ ?? A ?? Ah ?? Note: You do not actually have the string "\ 3619 \ 3657 \ 3634 \ 3609 \ 3648 \ 3592 \ 3657 \ 3648 \ 3621 \ 3657 \ 3591" - Instead, you have the UTF-32 string Is responsive ?? Responsible ?? A.K. ?? ¸ à ¥ ๠?? Ah ?? , for which "\ 3619 \ 3657 ..." is an ASCII-compliant literal By default, show example to display GHCI results , Which does not do much to show things can be used as the Haskell code for words In the case of Unicode, it is conservative because this is the reason

Prelude & gt; "¸ £ ¹ ?? ¸² ¸ ¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸¸ ?? ¸¸¸ ?? ¤ ?? ¤ ?? ¥ ๠?? ภ??" "3619 \ 3657 \ 3634 \ 3609 \; On the other hand, the putStrLn , putChar , code> hPutStr In -8 will dump the string instead of an ASCII-protected representation.

If you are actually reading a string that prevents a file or something, you can simply read :

prelude & gt; S & lt; One - ??? GetLine
"3619 \ 3657 \ 3634 \ 3609 \ 3648 \ 3592 \ 3657 \ 3648 \ 3621 \ 3657 \ 3591"
Prelude & gt; S "" \\ \\ 3619 \\ 3657 \\ 3634 \\ 3609 \\ 3648 \\ 3592 \\ 3657 \\ 3648 \ 3621 \ \ 3657 \ "3591 \" "<<"> - - Note double escaping, because I am showing a string in which the string is literal.
Prelude & gt; PutStrLn $ s read? / Blockquote>

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