java - How to compile multiple proto files in single command? -

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I have a protocol file which is in the directory alone and I am looking for a way to create classes in single command of those files I am Protobuf documentation says that we need to use the - proto_path argument for this. 

  C: \ Shekhar \ proto_trial> Drive C is the directory of dir volume c: \ shaker \ prototo_trial 07/25/2014 12:16 pm & lt; DIR & gt; . 07/25/2014 12:16 pm & lt; DIR & gt; .. 07/25/2014 12:16 pm & lt; DIR & gt; Java_op 07/25/2014 12:16 230 map.proto 07/23/2014 04:24 PM 161 message.proto 07/25/2014 12:17 PM 1,228 responses. Proto 3 files 1,619 bytes 3dir (s) 50,259,398,656 bytes free   
 I have used the  - proto_path  argument below  
  C: \ Shekhar \ proto_troll> Protocol --proto_path = C: \ Shekhar \ proto_trial - java_out = c: \ shekhar \ proto_trial \ java_op * .proto   
 but I am getting the following error  
  message.proto: The file is not within any path specified using --proto_path (or -i). You must specify a --proto_path that contains this file. Note that Proto_path should have an exact prefix of .proto file names - the protocol is very sensible, when two paths (like absolute and relative) are equivalent (it sounds as hard as you think).   
 Please suggest some ways to collect all prototypes in one shot.   
 
 
 The problem is that you specify  - proto_path  as a full path , But specify your protota files as relative paths. You can either drop the  - proto_path  argument (this is the default for the current directory), or you can do this:  
  Protocol --proto_path = C : \ Shekhar \ Proto_trial - java_out = c: \ shekhar \ proto_trial \ java_op c: \ shekhar \ proto_trial \ *. Prototype

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